Question

ayudenme porfavoor :(

Answer 1

(x + y) # (y + z) # (x + z) = x^4 + y^3 + z^2

8 # 14 # 12
Hallando valores:
x + y = 8
y + z = 14
x + z = 12
Sumando:
2x + 2y + 2z = 34
2(x + y + z) = 34
(x + y + z) = 34/2
x + y + z = 17
Si: x + y = 8
Tenemos:
x + y + z = 17
8 + z = 17
z = 17 - 9
z = 8
Si: y + z = 14
Tenemos:
x + y + z = 17
x + 14 = 17
x = 17 - 14
x = 3
Si: x + z = 12
Tenemos:
x + y + z = 17
y + x + z = 17
y + 12 = 17
y = 17 - 12
y = 5

x = 3; y = 5; z = 9
Entonces:
8 # 14 # 12 = (3 + 5) # (5 + 9) # (3 + 9)
Luego:
(3 + 5) # (5 + 9) # (3 + 9) = 3^4 + 5^3 + 9^2
(3 + 5) # (5 + 9) # (3 + 9) = 81 + 125 + 81
(3 + 5) # (5 + 9) # (3 + 9) = 287
Respuesta: Clave "d"