Question

$log_{2^{2} } 2^{(-2)}$

Answer 1

Explicación paso a paso:

or log | x V2v + v2 1 = log C log x / 2xy + y2 = logo or [ Putting v = Y ] or or ... ( 1 ) x12xy + y2 = C x2 ( 2xy + y2 ) = C2

espero te sirva xd