Question

Si: $\frac{a}{4}$ = $\frac{b}{3}$ = $\frac{c}{5}$ y $\frac{23ab}{3a + 2b + c}$ = 60 hallar el valor de: (3b-c)

Answer 1

Explicación paso a paso:

a/4=b/3=c/5

a=4b/3

c=5b/3

23ab/3a+2b+c=60

[23(4b/3)(b)] / [4b+2b+5b/3]=60

92b²/3/23b/3=60

92b²/23b=60

92b=1380

b=15

c=5b/3

c=5(15)/3

c=75/3

c=25

calcula:

3b-c

3(15)-25

45-25

20

saludos y sígueme