Question

El aluminio reacciona con el acido clorhidrico se produce cloruro de aluminio y gas hidrogéno calcula cuantos litros de hidrogeno, medidosa 273 k y 1atm, se obtiene cuando reaccionan totalmente 4,0 g de aluminio

Answer 1

Aplicar la LEY DE LOS GASES IDEALES: P x V = n x R x T (a)

T = 273 K
P = 1 atm.
V = ?
R = 0.0821 ( L atm /mol K)
m (Al ) = 4 g
Mm Al = 27 g/mol

                        2Al +  6HCl →  2AlCl3 +  3H2
 
1. calcular moles de Aluminio

moles Al = 4 g Al  x 1 mol Al
                                ````````````
                                27 g Al

moles Al = 0.148

2. calcular moles de H2

mol O2 = 0.148 mol Al  x  3 mol H2
                                          `````````````
                                           2 mol Al

mol O2 = 0.222

3. calcular V (L) despejado de la fórmula (a)

V = 0.222 moles x 0.0821 (L atm/molK) x 273 K
     ``````````````````````````````````````````````````````````````
                             1 atm

V = 4.975 litros de Oxigeno