Question

x2+11x-18 igual 0 me pueden ayudar

Answer 1

SOLUCIÓN

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                   $Sea\:la\:ecuaci\'on\:cuadr\'atica:\\\\ax^2+bx+c=0\\\\\\Por\:f\'ormula\:general\:tenemos\:que:\\\\\mathrm{\boxed{x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}}\\\\\\Del\:problema:\\\\a=1,b=11,c=-18\\\\\\ Entonces\:reemplazamos\\\\x_{1,2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x_{1,2}=\dfrac{-(11)\pm \sqrt{(11)^2-[4(1)(-18)]}}{2(1)}\\\\\\x_{1,2}=\dfrac{-11\pm \sqrt{121-(-72)}}{2}\\\\\\x_{1,2}=\dfrac{-11\pm \sqrt{193}}{2}\\\\\\x_{1,2}=\dfrac{-11\pm13.8924}{2}$

                $\Rightarrow\:x_{1}=\dfrac{-11+13.8924}{2}\\\\\\x_{1}=\dfrac{2.89244}{2}\\\\\\\boxed{\boldsymbol{x_{1}=1.44622}}\\\\\\\Rightarrow\:x_{2}=\dfrac{-11-13.8924}{2}\\\\\\x_{2}=\dfrac{-24.8924}{2}\\\\\\\boxed{\boldsymbol{x_{2}=-12.4462}}$

Answer 2

Respuesta:

Mover todos los términos al lado izquierdo e igualar a cero. Luego establecer cada factor sea igual a cero x = 9,2