Question

(x-4)/5=[(x-2)/3]+5
help

Answer 1

Ecuaciones

$\bf \dfrac{x-4}{5}= \dfrac{x-2}{3} + 5 \qquad primero\ resolvemos\ la\ suma\\ \\ \\ \dfrac{x-4}{5}= \dfrac{(x-2)+3*5}{3}\\ \\ \\ \dfrac{x-4}{5}= \dfrac{(x-2)+15}{3}\\ \\ \\ \dfrac{x-4}{5}= \dfrac{x+13}{3}\qquad Pasamos\ multiplicando \ los\ denominadores\\ \\ \\ 3*(x-4)= 5*(x+13)\qquad aplicamos \ distributiva\\ \\ \\ 3x-12= 5x+65\qquad Juntamos \ las\ x\\ \\ \\ 3x-5x=65+12\\ \\ -2x= 77\\ \\ \\ x=- \dfrac{77}{2}$

Espero que te sirva, salu2!!!!