Question

x+2y+2z=20
3x+2y+4z=40
2x+3y+2=30

Answer 1

SOLUCION

x+2y+2z=20

3x+2y+4z=40

2x+3y=28

x+2y+2z=20

3x+2y+4z=40

x= 14 - $\frac{3}{2\\}$ y

14- $\frac{3}{2}$y+2y+2z=20

3(14- $\frac{3}{2}$y) + 2y +4z =40

y+4z=12

-5y+8z= -4

5y+20z=60

-5y+8z= -4

28z=56

z=2

-5y+8x2= -4

y=4

x=14- $\frac{3}{2}$ x 4

x=8

(x,y,z)=(8,4,2)

8+2x4+2x2=20

3x8+2x4+4x2=40

2x8+3x4+2=30

20=20

40=40

30=30

RESPUESTA:

(x,y,z)=(8,4,2)