Question

(x+1)(x+5)=
(x-10((x-3)
(z+2)(z-7)=​

Answer 1

Respuesta:

${x}^{2} + 6x + 5$

${x}^{2} - 13x + 30$

${z}^{2} - 5z - 14$

Explicación paso a paso:

$(x + 1)(x + 5) \\ {x}^{2} + 5x + x + 5 \\ {x}^{2} + 6x + 5$

$(x - 10)(x - 3) \\ {x}^{2} - 3x - 10x + 30 \\ {x}^{2} - 13x + 30$

$(z + 2)(z - 7) \\ {z}^{2} - 7z + 2z - 14 \\ {z}^{2} - 5z - 14$