Una muestra de un gas ideal ocupa un volumen de 68.1ml a 945torr y 18°c que volumen ocupara a 118°c y 745 torr?
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V1 = 68.1 mL / 1000 = 0.0681 L
P1 =945 / 760 = 1.2434 atm
T1 = 18 ºC + 273 = 291 K
V2 = ?
P2 = 745 / 760 = 0.9803 atm
T2 = 118 ºC + 273 = 391 K
V1 P1 = V2 P2 (Ley general de los Gases)
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T1 T2
V2 = 0.0681 L x 1.2434 atm x 391 K
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0.1903 atm x 291 K
V2 = 0.597 L
P1 =945 / 760 = 1.2434 atm
T1 = 18 ºC + 273 = 291 K
V2 = ?
P2 = 745 / 760 = 0.9803 atm
T2 = 118 ºC + 273 = 391 K
V1 P1 = V2 P2 (Ley general de los Gases)
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T1 T2
V2 = 0.0681 L x 1.2434 atm x 391 K
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0.1903 atm x 291 K
V2 = 0.597 L
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