Question

un cuerpo cae libremente desde 845m.¿con que velocidad llego al piso? gravedad=10 m/s^2​

Answer 1

Respuesta:

V=−128.693m/s

V = 0 − gt = - (9.8m / s

two

) (13.13s) (6) 0 = 845m−

two

1

.

(9.8m / s

two

) t

two

(3)

t = \ sqrt {\ frac {2 (845m)} {9.8m / s ^ {2}}} t =

9.8m / s

two

2 (845m)

.

.

(4)

t = 13.13st = 13.13s (5) Answer: (a) t = 13.13 s (b) V = -1 ES 128.693 M/S en minúscula m/s