Question

Un compuesto contiene 32.74% de estaño, 1.10% de hidrogeno, 13.25% de carbono y 52.91 de oxigeno. Determina la formula empirica.

Answer 1

Sn = 32,74 g / 118,7 g/mol = 0.2758 mol
H = 1,10 g / 1 g/mo = 1,10 mol
O = 52,91 g / 16 g/mol = 3.306 mol

Sn = 0.2758 mol / 0.2758 mol = 1
H =1,10 mol / 0.2758 mol = 4
O = 3,306 mol / 0.2758 mol = 12

FE = HSn₄O₁₂