Question

Solucionar el binomio
X+1)²=
(X-1)²=
(3+6)²
(4B+3C)²
(56+36)²
(2A-3B)²
(1,5xy²+2'5xy)²

Answer 1

Explicación paso a paso:

Binomio al  cuadrado:

(a ± b)² = a² ± 2ab + b²

(x+1)² = (x)²+2(x)(1)+(1)²

(x + 1)² = x²+2x+1

(x-1)² = (x)²-2(x)(1)+(1)²

(x - 1)² = x²-2x+1

(3+6)² = (3)²+2(3)(6)+(6)²

(3 + 6)² = 9+36+36

(4B+3C)² = (4B)²+2(4B)(3C)+(3C)²

(4B + 3C)² = 16B²+24BC+9C²

(56+36)² = (56)²+2(56)(36)+(36)²

(56 + 36)² = 3136+4032+1296

(2A-3B)² = (2A)²-2(2A)(3B)+(3B)²

(2A - 3B)² = 4A²-12AB+9B²

(1,5xy²+2,5xy)² = (1,5xy²)²+2(1,5xy²)(2,5xy)+(2,5xy)²

$(1.5xy^{2} +2.5xy)^{2} = \frac{9}{4}x^2y^{4}+\frac{15}{2}x^2y^{3}+\frac{25}{4}x^2y^2$