solucion de desigualdades 4X-1>16X+14,
4X-4<12
6X+5<2X-15,
9X+14<6x-12,
X²-2X-15>0,
X²+x-6>0,
X²-6X+5>0
Respuestas a la pregunta
Respuesta:
3X²-12≥0
\begin{gathered}3 {x}^{2} = 12 \\ {x}^{2} = 4 \\ x = \sqrt{4 } \\ x = 2\end{gathered}
3x
2
=12
x
2
=4
x=
4
x=2
X² ≤ 4x+ 12
\begin{gathered} {x}^{2} \leqslant 4x + 12 \\ {x}^{2} - 4x - 12 \\ (x - 6)(x + 2) \leqslant 0 \\1) x - 6 \leqslant 0 \\ x \leqslant 6 \\ 2)x + 2 \leqslant 0 \\ x + \leqslant - 2\end{gathered}
x
2
⩽4x+12
x
2
−4x−12
(x−6)(x+2)⩽0
1)x−6⩽0
x⩽6
2)x+2⩽0
x+⩽−2
16X²-64>0
\begin{gathered}16 {x}^{2} - 64 > 0 \\ {x}^{2} = 4 \\ x = 2\end{gathered}
16x
2
−64>0
x
2
=4
x=2
6X²-5<x
\begin{gathered}6 {x}^{2} -x - 5 < 0 \\ (6x -5)(x + 1) < 0 \\ 1)6x - 5 < 0 \\ x = \frac{5}{6} \\ 2)x + 1 < 0 \\ x < -1\end{gathered}
6x
2
−x−5<0
(6x−5)(x+1)<0
1)6x−5<0
x=
6
5
2)x+1<0
x<−1
X²-2x-4≥3
\begin{gathered} {x}^{2} - 2x - 7 \geqslant 0 \\ \end{gathered}
x
2
−2x−7⩾0