Question

si: senx+cosx=n
hallar
E=tgx+ctgx+secx+cscx

Answer 1

$\sin(x)+\cos(x)=n \\ E=\tan(x)+\cot(x)+\sec(x)+\csc(x) = \frac{\sin(x)}{\cos(x)} + \frac{\cos(x)}{\sin(x)} + \frac{1}{\cos(x)} + \frac{1}{\sin(x)} \\ = \frac{sin(x)+1}{\cos(x)} + \frac{\cos(x)+1}{sin(x)} \\ = \frac{sin^2(x)+sin(x)+cos^2(x)+cos(x)}{\sin(x)*\cos(x)} \\ sin^2(x)+cos^2(x)=1 \\ sin(x)+cos(x)=n \\ E= \frac{n+1}{sin(x)*cos(x)}$

Answer 2

Explicación paso a paso:

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