Question

Si: F(x)=2x³+2x²-x+4 Q(x)=x³+x²+2x+3
Hallar: F(x)-2Q(x)​

Answer 1

$2 {x}^{3} + 2 {x}^{2} - x + 4 - 2( {x}^{3} + {x}^{2} + 2x + 3) = \\ 2 {x}^{3} + 2 {x}^{2} - x + 4 - 2 {x}^{3} - 2 {x}^{2} - 4x - 6 = \\ (2 {x}^{3} - 2 {x}^{3} ) + (2 {x}^{2} - 2 {x}^{2} ) + ( - x - 4x) + (4 - 6) = \\ - 5x + ( - 2) = \\ - 5x - 2$