Question

Si f(x)=2x^3+9x^2+8x-2 ,¿cuánto es f(-2)?

Answer 1

Respuesta:

f(x) = 2x³+9x²+8x-2 ; x = -2

f(-2) = 2(-2)³+9(-2)²+8(-2)-2 ; (-2)³ = -8 y (-2)² = 4

f(-2) = 2(-8)+9(4)+8(-2)-2 ; 2(-8) = 8(-2) = -16

f(-2) = -16+9(4)+(-16)-2 ; 9(4) = 36

f(-2) = -16+36-16-2

f(-2) = (-16-16-2)+36

f(-2) = (-32-2)+36

f(-2) = -34+36

f(-2) = 2

R// El valor de calculae " f(-2) " es 2 .

Answer 2

2

Explicación paso a paso:

2(-2)^3+9(-2)^2+8(-2)-2

-16. +36. -18

-16-18+36

=2