Question

Si: (a-4)a(a-4) (6) = xy y 4). Hallar x+y+z​

Answer 1

Respuesta:

x = 3a³ - 24a² + 48a

________________ , y ≠ 0

2y

Resolución paso a paso:

(a - 4) a × (a - 4) × 6= xy × 4

(a - 4 ) × 6a × (a - 4) = 4yx

(a - 4)² × 6a = 4yx

6a × (a - 4)² = 4yx

6a × (a² - 8a + 16) = 4yx

6a³ - 48a² + 96a = 4yx

4yx = 6a³ - 48a² + 96a

x = 6a³ - 48a² + 96a

______________ , 4y ≠ 0

4y

x = 6a³ - 48a² + 96a

______________ , y ≠ 0

4y

x = 2 (3a³ - 24a² + 48a)

_______________ , y ≠ 0

4y

x = 3a³ - 24a² + 48a

______________ , y ≠ 0

2y