Question

Sea
f(x) = ax2 + bx + c.
Si:
f(0) = –2 ; f(1) = 6 y
f(3) + f(2) = 76.
Determina el valor de: 3a + 2b + c.

Answer 1

Para:

x = 0  a.02 + b.0 + c= –2  c= –2

x = 1  a.12 + b.1 + c = 6  a + b = 8  - - - (1)

x = 3  a.32 + b.3 + c = 9a + 3b – 2

x = 2  a.22 + b.2 + c = 4a + 2b –

    13a + 5b – 4 = 76 - - - (2)

De (1) y (2):  a = 5 ; b = 3 y c = –2

Entonces:  

3.5 + 2.3 – 2 = 19

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