Question

S = 1im น 45in VSnZX 3x² tan 4x cost​

Answer 1

Respuesta:

Solution

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LHS :

tan4x=tan[2(2x)]

=

1−tan

2

2x

2tan2x

=

1−(

1−tan

2

x

2tanx

)

2

2(

1−tan

2

x

2tanx

)

=

(1−tan

2

x)

2

−4tan

2

x

4tanx(1−tan

2

x)

=

1−6tan

2

x+tan

4

x

4tanx(1−tan

2

x)

= RHS