Question

resuelva las sumas y restas de fracciones heterogeneas y una con la respuesta correcta​

Answer 1

Respuesta:

$\frac{3}{5} + \frac{6}{4} = \frac{12 + 30}{20} \frac{42}{20} = 2 \frac{1}{10}$

$\frac{1}{8} + \frac{4}{6} = \frac{6 + 32}{48} = \frac{38}{48} = \frac{19}{24}$

$\frac{6}{10} + \frac{9}{5} = \frac{6 + 18}{10} = \frac{24}{10} = \frac{12}{5} = 2 \frac{2}{5}$

$\frac{18}{8} - \frac{7}{5} = \frac{90 - 56}{40} = \frac{34}{40} = \frac{17}{20}$

$\frac{7}{10} - \frac{2}{5} = \frac{7 - 4}{10} = \frac{3}{10}$

$\frac{9}{12} - \frac{4}{8} = \frac{72 - 48}{96} = \frac{24}{96} = \frac{2}{8} = \frac{1}{4}$

$\frac{2}{5} + \frac{1}{3} = \frac{6 + 5}{15} = \frac{11}{15}$

$\frac{8}{2} + \frac{4}{8} = \frac{64 + 8}{16} = \frac{72}{16} = \frac{9}{2} = 4 \frac{1}{2}$

$\frac{2}{7} + \frac{9}{3} = \frac{6 + 63}{21} = \frac{69}{21} = \frac{23}{7} = 3 \frac{2}{7}$

Espero haberte ayudado (:

Answer 2

Respuesta:

no sé yo tampoco para ayudarte amigo