Question

resolver las siguientes ecuaciones lineales 4m-3=5m+3/2 b) 2x-1/5=3x+1/3 c) 7y-4/5=3y+1 d) 3y/5+1/3=y/2-4/5

Answer 1

Ahi te va la silucion....

Answer 2

a).
4m - 3 = 5m + 3/2
4m - 3  = (10m + 3)/2
2(4m - 3) = 10m +3
8m - 6 = 10m + 3
-2m = 9
m = -9/2

b).
2x - 1/5 = 3x + 1/3
(10x - 1)/5= (9x + 1)/3
3(10x - 1) = 5(9x + 1)
30x - 3 = 45x + 5
-15x = 8
x = -8/15

c).
7y - 4/5 = 3y + 1
(35y + 4)/5 = 3y + 1
35y - 4 = 5(3y + 1)
35y - 4 = 15y +5
20y = 9
y = 9/20

d).
3y/5 + 1/3 = y/2 - 4/5
(9y + 5)/15 = (5y - 8)/10
10(9y + 5) = 15(5y - 8)
90y + 50 = 75y - 120
15y = -170
y = -170/15 (sacamos 5ta)
y = -34/3
o
y = -11.333...periódico puro