Question

resolver las siguiente ecuaciones
1. (×+1)(2×+5)=(2×+3)(×-4)+5
a. x=2
b.×=1
c.×=-3
d. ×=-1

2. 2(3×+3)-4(5×-3)=×(×-3)-×(×+5)
a. x=3
b. x=-2
c. x=5
d. x=-4

3. ×-2/3+×+1/6-×-1/4=1
×=5
×=-7
×=3
×=-6

4. 15-[-3×+(8×-2)]=7
×=4
×=2
×=-3
×=-1​

Answer 1

Respuesta:

Explicación paso a paso:

(× + 1)(2× + 5) = (2× + 3)(×  - 4) + 5

2x^2 + 5x + 2x + 5 = 2x^2 - 8x + 3x - 12 + 5

2x^2 + 7x + 5 = 2x^2 - 5x - 7

2x^2 - 2x^2 + 7x + 5x = - 7 - 5

12x = -12

x = -12/12

x = -1

2(3× + 3) - 4(5× - 3) = ×(× - 3) - ×(× + 5)

6x + 6 - 20x + 12 = x^2 - 3x - x^2 - 5x

6x - 20x + 6 + 12 = x^2 - x^2 -3x - 5x

- 14x + 18 = - 8x

18 = - 8x + 14x

18 = 6x

18/6 = x

x = 3

× - 2/3 + × + 1/6 - × - 1/4 = 1

x + x - x - 2/3 + 1/6 - 1/4 = 1

x - 2/3 + 1/6 - 1/4 = 1

x - 1/2 - 1/4 = 1

x - 3/4 = 1

x = 1 + 3/4

x = 7/4 (Está corroborado, quizá escribiste mal la ecuacion.)

15 - [ - 3x + (8x - 2) ] = 7

15 - [ - 3x + 8x - 2 ] = 7

15 - [ 5x - 2 ] = 7

15 - 5x + 2 = 7

17 - 5x = 7

17 - 7 = 5x

10 = 5x

10/5 = x

2 = x

Answer 2

Respuesta:

1) -1

2)x=3

3)×=3

4)×=2

Explicación paso a paso: