Question

Resolver:
(3x^2 y^4 )(-5xy^5 )




(-2a^2 b^4 )(7ab^3+4ab-5)




Son polinomios, multiplicacion de polinomios

Answer 1

Respuesta:

no se 123

Explicación paso a paso:

.

Answer 2

$\left(3x^2y^4\right)\left(-5xy^5\right)$

$\mathrm{Aplicar\:la\:propiedad}:\quad \:a\left(-b\right)=-ab$

$\left(3x^2y^4\right)\left(-5xy^5\right)=-3x^2y^4\cdot \:5xy^5$

$=-3x^2y^4\cdot \:5xy^5$

$\mathrm{Multiplicar\:los\:numeros:}\:-3\cdot \:5=-15$

$=-15x^2y^4xy^5$

$=-15x^3y^4y^5$

Respuesta: $=-15x^3y^9$

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$\left(-2a^2b^4\right)\left(7ab^3+4ab-5\right)$

$\mathrm{Aplicar\:la\:propiedad}:\quad \left(-a\right)=-a$

$\left(-2a^2b^4\right)=-2a^2b^4$

$=-2a^2b^4\left(7ab^3+4ab-5\right)$

$\mathrm{Poner\:los\:parentesis\:utilizando}:\quad \:m\left(a+b+c\right)=ma+mb+mc$

$-2a^2b^4\left(7ab^3+4ab-5\right)=-2a^2b^4\cdot \:7ab^3-2a^2b^4\cdot \:4ab-2a^2b^4\left(-5\right)$

$=-2a^2b^4\cdot \:7ab^3-2a^2b^4\cdot \:4ab-2a^2b^4\left(-5\right)$

Respuesta:  $= -14a^3b^7-8a^3b^5+10a^2b^4$