Question

Quien me ayudaaaaaa!??
Es Identidades Trigonométricas

Answer 1

${\frac{sen^2x+cos^2x+tan^2x}{secx}=}\\\\{ \frac{1+tan^2x}{secx}=}\\\\{ \frac{1+\frac{sen^2x}{cos^2x}}{\frac{1}{cosx}} =}\\\\{\frac{\frac{cos^2x+sen^2x}{cos^2x}}{\frac{1}{cosx}}=}\\\\{\frac{\frac{1}{cos^2x}}{\frac{1}{cosx}}=}\\\\{\frac{1}{cos^2x} \times \frac{cosx}{1}=}\\\\{\frac{1}{cosx}=}\\\\{\boxed{secx}}\\\\{\mathbf{salu2.!!\ :)}}\\{\mathbf{Wellington}}$