Question

que me lo resuelva alguien porfavor ​

Answer 1

Respuesta:

37 a)

$- 2 + \frac{3}{6} = - \frac{12}{6} + \frac{3}{6} = - \frac{9}{6} = - \frac{3}{2} = - 1 \frac{1}{2}$

37 b)

$\frac{3}{ - 5} + ( - \frac{ 2 }{7} ) = - \frac{3}{5} - \frac{2}{7} = \frac{ - 3(7) + ( - 2)(5)}{35} = \frac{ - 21 - 10}{35} = \frac{ - 31}{35} = - \frac{31}{35}$

37 c)

$\frac{ - 2}{5} + ( - 5) = - \frac{2}{5} - 5 = - \frac{2}{5} - \frac{25}{5} = - \frac{27}{5} = - 5 \frac{2}{5}$

37 d)

$- ( \frac{ - 1}{4} ) - ( - \frac{5}{6} ) = \frac{1}{4} + \frac{5}{6} = \frac{1(3) + 5(2)}{12} = \frac{3 + 10}{12} = \frac{13}{12} = 1 \frac{1}{12}$

38 a)

$\frac{1}{5} - 2 + ( - \frac{4}{9} ) = \frac{1}{5} - 2 - \frac{4}{9} = \frac{1(9) - 2(45) - 4(5)}{45} = \frac{9 - 90 - 20}{45} = \frac{ - 101}{45} = - 2 \frac{11}{45}$

38 b)

$\frac{5}{3} - ( - \frac{4}{9} ) + ( \frac{5}{ - 6} ) = \frac{5}{3} + \frac{4}{9} - \frac{5}{6} = \frac{5(6) + 9(2) - 5(3)}{18} = \frac{60 + 18 - 15}{18} = \frac{63}{18} = 3 \frac{9}{18} = 3 \frac{1}{2}$

38 c)

$1 - ( \frac{3}{ - 5} ) + ( - \frac{2}{7} ) = 1 + \frac{3}{5} - \frac{2}{7} = \frac{1(35) + 3(7) - 2(5)}{35} = \frac{35 + 21 - 10}{35} = \frac{46}{35} = 1 \frac{11}{35}$

38 d)

$- ( \frac{1}{ - 2} ) - 5 + ( \frac{ - 3}{4} ) = \frac{1}{2} - 5 - \frac{3}{4} = \frac{1(4) - 5(8) - 3(2)}{8} = \frac{4 - 40 - 6}{8} = \frac{ - 42}{8} = - 5 \frac{2}{8} = - 5 \frac{1}{4}$