Question

procedimiento ( ･ั﹏･ั)(｡•́︿•̀｡)​

Answer 1

Respuesta:

Explicación paso a paso:

$0.1$

$E = (Sen 30+Cos60) Tan37$

$E = (\frac{1}{2}+\frac{1}{2} )*(\frac{3}{4} ) = (1)*(\frac{3}{4})$

$E = \frac{3}{4}$

RESPUESTA:

   $\frac{3}{4}$

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$0.2$

$F = \frac{4*Sen30+\sqrt{3}*tan60 }{10*Cos37+\sqrt{2}Sec45 }$

$F = \frac{4*(\frac{1}{2} )+(\sqrt{3})*(\sqrt{3} ) }{10*(\frac{4}{5})+(\sqrt{2})*(\sqrt{2} ) } =\frac{2+3}{8+2} =\frac{5}{10}$

$F = \frac{1}{2}$

RESPUESTA:

       $\frac{1}{2}$

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$0.3$

$E = \sqrt{6} *tg30*Sec45+3Sec53$

$E =( \sqrt{6} )*(\frac{\sqrt{3} }{3} )*(\sqrt{2} ) + 3(\frac{5}{3} ) = \frac{(\sqrt{6})*(\sqrt{6)} }{3} +\frac{15}{3} = \frac{6}{3} +\frac{15}{3} = 2+5$

$E = 7$

RESPUESTA:

      $7$

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$0.4$

$E = Sec 37 + Ctg53 -2 Sen30$

$E =\frac{5}{4} + \frac{3}{4} -2(\frac{1}{2} ) =\frac{5+3}{4} -\frac{2}{2} = \frac{8}{4} -\frac{2}{2} = 2-1$

$E = 1$

RESPUESTA:

        $1$

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$0.5$

$5x* Sen 53 +2Sec60 = xtg45+Sec^{2} 45$

$(5x)* (\frac{4}{5} ) -2(2)= x (1)-2(\frac{1}{2} )$

$4x-4 = x -1$

$4x-x = -1 +4$

$3x= 3$

$x = \frac{3}{3} = 1$

$x= 1$

RESPUESTA:

        $1$

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$0.6$

$Tg (2x-5) = Sen^{2} 30 + Sen^{2} 60$  

$Tg (2x-5 ) = (\frac{1}{2} )^{2} + (\frac{\sqrt{3} }{2} )^{2}$

$Tg ( 2x-5 ) = \frac{1}{4} +\frac{3}{4}$

$Tg(2x-5 ) = \frac{1+3}{4}$

$Tg(2x-5 ) = \frac{4}{4}$

$Tg(2x-5) = 1$

$(2x-5 ) = ArCTg(1)$

$2x-5 = 45$

$2x = 45+5$

$2x = 50$

$x = \frac{50}{2} = 25$

RESPUESTA:

    $25^{0}$