Porfa ayudenmen en esta pregunta?
Cual es el peso molecular de un gas si 0,797gr. Estan ocupando un volumen de 1,22L A 27°C Y 1 atm. De Presion
Respuestas a la pregunta
Contestado por
2
Ley de los gases ideales
V · P = n · R · T sustituir n
n = masa/Mm
V · P = masa · R · T despejar Mm
``````````
Mm
Mm = m · R · T
``````````````
V · P
R = 0.0821 (L atm/mol K)
T = 27 ºC + 273 = 300 K
P = 1 atm
V = 1.22 L
m = 0.797 g
Mm = 0.797 g · 0.0821 (L atm / mol K) · 300 K
````````````````````````````````````````````````````````
1 atm · 1.22 L
Mm = 16.09 g/mol
V · P = n · R · T sustituir n
n = masa/Mm
V · P = masa · R · T despejar Mm
``````````
Mm
Mm = m · R · T
``````````````
V · P
R = 0.0821 (L atm/mol K)
T = 27 ºC + 273 = 300 K
P = 1 atm
V = 1.22 L
m = 0.797 g
Mm = 0.797 g · 0.0821 (L atm / mol K) · 300 K
````````````````````````````````````````````````````````
1 atm · 1.22 L
Mm = 16.09 g/mol
Otras preguntas