POR FAVOR AYUDENME ES PARA MAÑANA
Respuestas a la pregunta
Respuesta:
Nivel 2
1. c) 3
2. a) π rad
3. b) 5π / 3 rad
Asume el reto
1. b) π / 3 rad
2. d) π / 10 rad
Explicación paso a paso:
Nivel 2
1.
S / 9 = C / 10 = R / (π / 20) = q
S = 9q
C = 10q
N = ⁵√[(10(10q) + 12(9q)) / (10q - 9) + 35]
N = ⁵√[(100q + 108q) / q + 35]
N = ⁵√[208q / q + 35]
N = ⁵√[208 + 35]
N = ⁵√243
N = 3
2.
S / 180 = C / 200 = R / π = k
S = 180k
C = 200k
R = πk
S + C + R = 383,1416
180k + 200k + πk = 380 + 3,1416
380k + πk = 380 + π
k(380 + π) = 380 + π
k = 1
R = πk
R = π rad
3.
S / 180 = C / 200 = R / π = k
S = 180k
C = 200k
R = πk
(200k + 2(πk)) / (200k - 2(πk)) = (180k + 3π) / (180k - 3π)
(200k + 2πk) / (200k - 2πk) = (180k + 3π) / (180k - 3π)
2k(100 + π) / (2k(100 - π)) = 3(60k + π) / (3(60k - π))
(100 + π) / (100 - π) = (60k + π) / (60k - π)
60k = 100
k = 100 / 60
k = 5 / 3
R = πk
R = π(5 / 3)
R = 5π / 3 rad
Asume el reto
1.
S / 180 = C / 200 = R / π = k
S = 180k
C = 200k
R = πk
180k / 12 + 3(200k) / 10 + 6(πk) / π = 27
15k + 3(20k) + 6k = 27
15k + 60k + 6k = 27
81k = 27
k = 27 / 81
k = 1 / 3
R = π(1 / 3)
R = π / 3 rad
2.
S / 180 = C / 200 = R / π = k
S = 180k
C = 200k
R = πk
(180k / 3 - 200k / 5)² - 20(πk) / π > 0
(60k - 40k)² - 20k > 0
(20k)² - 20k > 0
20k(20k - 1) > 0
20k = 0
k = 0
20k - 1 = 0
20k = 1
k = 1 / 20
+ - +
<----------o---------------o--------------->
- ∞ 0 1 / 20 + ∞
k < 0 o k > 1 / 20
k = 1 / 10, 1 / 5, 1 / 2
k = 1 / 10
R = π(1 / 10)
R = π / 10 rad