Question

pliss ayúdenme, necesito resolverlos con la fórmula general ​

Answer 1

Respuesta: Ignora las Â

a = 2 ; b = 4 ; c = 8

$2x^{2} +4x+8=0\\x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}\\x=\frac{-4±\sqrt{4^{2}-4(2)(8) } }{2(2)}\\x=\frac{-4±\sqrt{-48 } }{4}\\\\x=\frac{-4±i\sqrt{(2^{4})(3) } }{4}\\x=\frac{-4±4i\sqrt{(3) } }{4}\\\x=-1±i\sqrt{3}$

a = 4 ; b = 12 c = 9

$4x^{2} +12x+9=0\\x=\frac{-12±\sqrt{(12^{2})-4(4)(9) } }{2(4)} \\x=\frac{-12±\sqrt{0 }}{8} \\\x=\frac{-3±0}{2}$