Question

Estas dos preguntas son

Answer 1

12.

Mm NH3 = 17 g/mol
    Cs2O = 281.81 g/mol
       HCl = 36.45 g/mol

a. calcular moles de cada componente:

n NH3 = 43 g/ 17 g/mol = 2.53 mol
n Cs2O = 25 g/ 281.81 g/mol = 0.0089 mol
n HCl = 87 g / 36.45 g/mol = 2.38 mol

b. calcula n totales = nNH3 + nCs2O + n HCl

n totales = 2.53 mol + 0.089 mol + 2.38 mol = 4.999 moles ≈ 5 moles

c.  calcular fracción molar de cada componente

X NH3 = 2.53 mol / 5 mol = 0.506

XCs2O = 0.089 mol / 5 mol = 0.0178 mol

XHCl = 2.38 mol / 5 mol = 0.476 mol

13.

Mm NH3 = 17 g/mol
          N2 = 28 g/mol

a.

 na = sustancia 1
 nb = sustancia 2
n totales = 1

calcular moles de cada sustancia.

na = 0.17 x 1 mol = 0.17 mol
nb = 0.83 x 1 mol = 0.83 mol

b, calcular la composición porcentual y para ello se debe conocer la masa de cada sustancia aplicando la fórmula n=m/Mm

m 1 = na x MmNH3
m 2 = nb x Mm N2

la masa total (solución) = m1 + m2

aplicando la formula: %m/m = masa soluto x 100  (para calcular %)
                                               ``````````````````
                                                 masa total (solc)

%m/m  =  m 1   x   100    (SUSTANCIA 1)
                `````````
                   mt
                 

%m/m  =  m 2   x   100    (SUSTANCIA 2)
                `````````
                   mt