Question

Determine la fórmula empírica de un compuesto que contiene: K = 24,68% Mn = 34,81% O = 40,51%

Answer 1

K: 24.68 g / 39 g/mol = 0.632 mol

Mn: 34.81 g / 55 g/mol = 0.633 mol

O: 40.51 g / 16 g/mol = 2.531 mol

dividir

K: 0.632 mol / 0.632 mol = 1

Mm: 0.633 mol / 0.632 mol = 1

O: 2.531 mol = 0.632 mol = 4

FE = KMnO4 (PERMANGANATO DE POTASIO)