Question

determina el area del cuadrado si la base mide 1/3x^2 + 1/4y^2

Answer 1

Area del cuadrado 
$A= l^{2}$
$A= (\frac{1}{3} x^{2} + \frac{1}{4}y^{2})^{2}$
$A= \frac{1}{9} x^{4}+2( \frac{1}{3} x^{2} * \frac{1}{4}y^{2})+ \frac{1}{16}y^{4}$
$A= \frac{1}{9} x^{4}+ \frac{1}{6} x^{2}y^{2}+ \frac{1}{16}y^{4}$