Question

desarrollo de la cuenta 105+(4²+12+5²).(3⁴-2²)-√13-12​

Answer 1

= 105 + (4² + 12 + 5²) × (3⁴ - 2²) - √13-12
= 105 + (4 × 4 + 12 + 5 × 5) × (3 × 3 × 3 × 3 - 2 × 2) - √1
= 105 + (16 + 12 + 25) × (81 - 4) - √1
= 105 + (28 + 25) × (81 - 4) - √1
= 105 + (53 × 77) - √1
= 105 + 4.081 - √1
= 105 + 4.081 - 1
= 4.186 - 1
= 4.185 ✓

105 + (4² + 12 + 5²) × (3⁴ - 2²) - √13-12 = 4.185 ✓