Question

derivada de (senx + cosx)^3​

Answer 1

Respuesta:

${y}^{.} = 3(cosx - senx)(senx + cosx {)}^{2}$

Explicación:

$si \: y = (senx + cosx {)}^{3} \\ {y}^{.} = 3(senx + cosx {)}^{3 - 1} \times (senx + cosx {)}^{.}$

${y}^{.} = 3(senx + cosx {)}^{2} \times (cosx - senx)$

${y}^{.} = 3(cosx - senx)(senx + cosx {)}^{2}$