Question

Dados los términos semejantes, hallar a+b
(3a + 2b)m a+4b n -b-3a y ( + )m 13+2b n 1-5a

Answer 1

(3a + 2b) ma + 4bn - b - 3ay (+) m . 13 + 2bn . 1 - 5a

= (3a + 2b) ma + 4bn - b - 3aym . 13 + 2bn . 1 - 5a

= am (3a + 2b) + 4bn - b - 39amy + 2 . 1 . bn - 5a

= am (3a + 2b) + 4bn - b - 39amy + 2bn - 5a

= am (3a + 2b) + 4bn - b - 39amy + 2bn - 5a

EXPANDIR: ma (3a + 2b): 3a^2m + 2abm

= 3a^2m + 2abm + 4bn - b - 39aym + 2bn - 5a

SIMPLIFICAR: 3a^2m + 2abm + 4bn - b - 39aym + 2bn - 5a: 3a^2 m + 2abm - 39amy - 5a - b + 6bn

= 3a^2m + 2abm - 39amy - 5a - b + 6bn

Saludos!