Dado f(x) = x^2+3x+1 y g(x)=2x-3
Calcular:
A) (fog) (4)
B) (fof) (0)
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[f(x)=x^2+2x-3] / [g(x)=x^2+3x-4] =
= (x-1)*(x+3) / [(x+4)*(x-1)] =
= (x+3) / [(x+4)
b) f o g(x) =
f(g(x))=(x^2+3x-4)^2+2(x^2+3x-4)-3
c) g 0 f(x)
g(f(x)= (x^2+2x-3)^2+3(x^2+2x-3)-4
salu2
= (x-1)*(x+3) / [(x+4)*(x-1)] =
= (x+3) / [(x+4)
b) f o g(x) =
f(g(x))=(x^2+3x-4)^2+2(x^2+3x-4)-3
c) g 0 f(x)
g(f(x)= (x^2+2x-3)^2+3(x^2+2x-3)-4
salu2
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