cuantos moles estan presentes en 25 g de carbonato de sodio?CaCO3
Respuestas a la pregunta
Contestado por
19
por la fórmula CaCO3 = se trata de carbonato de calcio
Mm CaCO3 = 100 g/mol
n = m/Mm
n = 25 g/ 100 g/mol
n = 0.25 moles de CaCO3
`````````````````````````````````````````````````````````````````
Mm Na2CO3 = 105.98 g/mol (carbonato de sodio)
n = 25 g / 105.98 g/mol
n = 0.235 moles
Mm CaCO3 = 100 g/mol
n = m/Mm
n = 25 g/ 100 g/mol
n = 0.25 moles de CaCO3
`````````````````````````````````````````````````````````````````
Mm Na2CO3 = 105.98 g/mol (carbonato de sodio)
n = 25 g / 105.98 g/mol
n = 0.235 moles
Otras preguntas