Cuantos gramos de hidroxido de sodio se necesitan para preparar un litro de solucion 1m !
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Mm NaOH = 40 g/mol
1 L = 1 Kg
1. calcular moles soluto despejando de la fórmula
m = mol soluto /Kg Svte
mol soluto = 1 L x 1 mol /L
mol soluto = 1
2. calcular masa de NaOH
masa = 1 mol x 40 g
````````
1 mol
masa = 40 g de NaOH
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Como el ejercicio dice litro de solución
M = 1 mol / L
dspejar mol soluto de la fórmula de molaridad
M = mol soluto / V(L)
mol soluto = 1 mol /L x 1 L
mol = 1
calcular masa
masa = 1 mol x 40 g/mol
masa = 40 g de NaOH
M = 1 molar
1 L = 1 Kg
1. calcular moles soluto despejando de la fórmula
m = mol soluto /Kg Svte
mol soluto = 1 L x 1 mol /L
mol soluto = 1
2. calcular masa de NaOH
masa = 1 mol x 40 g
````````
1 mol
masa = 40 g de NaOH
``````````````````````````````````````````````````````````````````````````````````
Como el ejercicio dice litro de solución
M = 1 mol / L
dspejar mol soluto de la fórmula de molaridad
M = mol soluto / V(L)
mol soluto = 1 mol /L x 1 L
mol = 1
calcular masa
masa = 1 mol x 40 g/mol
masa = 40 g de NaOH
M = 1 molar
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