Question

cuales son los primeros 10 terminos de una sucesion si el inicial es 2/3 y la diferencia es 1/6

Answer 1

Respuesta:

Explicación paso a paso:

a(n) = 2/3 + (n - 1)(1/6)

a(n) = 4/6 + n/6 - 1/6

a(n) = n/6 - 3/6

a(n) = (n - 3)/6

a(1) = (1 - 3)/6 = -2/6 = -1/3

a(2) = (2 - 3)/6 = -1/6

a(3) = (3 - 3)/6 = 0

a(4) = (4 - 3)/6 = 1/6

a(5) = (5 - 3)/6 = 2/6 = 1/3

a(6) = (6 - 3)/6 = 3/6 = 1/2

a(7) = (7 - 3)/6 = 4/6 = 2/3

a(8) = (8 - 3)/6 = 5/6

a(9) = (9 - 3)/6 = 6/6 = 1

a(10) = (10 - 3)/6 = 7/6