Question

cuales son los primeros 10 terminos de una sucesión si el inicial es dos tercios y la diferencia entre dos términos consecutivis es un sexto

Answer 1

Tenemos.

d = 1/6

1er termino  = 2/3
2do termino = 2/3 +  1/6 = 4/6 + 1/6 = (4 + 1)/6 = 5/6
3er  termino = 5/6 + 1/6 = (5 +1)/6 = 6/6 = 1
4to termino = 6/6 + 1/6 = ( 6+1)/6 = 7/6
5to termino = 7/6 + 1/6 = (7 + 1)/6 = 8/6  simplificas = 4/3
6to termino = 8/6 + 1/6 = (8 + 1)/6 = 9/6  Simplificas = 3/2
7to termino = 9/6 + 1/6 = ( 9 + 1)/6 = 10/6 Simplificas = 5/3
8vo termino = 10/6 + 1/6 = (10 + 1)/6 = 11/6
9no termino = 11/6 + 1/6 = (11 + 1)/6 = 12/6 = 2
10mo termino = 12/6 + 1/6 = (12 +1)/6 = 13/6

Respuesta.
2/3 , 5/6 , 1 , 7/6 , 4/3 + 3/2 , 5/3 , 11/6 , 2 , 13/6