cual es la composición centesimal de NH4NO3 ,CaCo3 y H2O
Respuestas a la pregunta
Contestado por
42
Mm NH4NO3
N: 2 x 14 = 28 g/mol
H: 4 x 1 = 4 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 80 g/mol
NITROGENO:
80 g ------ 100 %
28 g ------ x
x = 35 % N
HIDROGENO:
80 g ------ 100 %
4 g ------ x
x = 5 % H
OXIGENO:
80 g ------ 100 %
48 g ------ x
x = 60 % O
B) CaCO3
Mm CaCO3
Ca: 1 x 40 = 40 g/mol
C: 1 x 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````````
Mm = 100 g/mol
Calcio
100 g ----- 100 %
40 g ----- x
x = 40 % Ca
Carbono
100 g ----- 100 %
12 g ----- x
x = 12 % C
OXIGENO
100 g ----- 100 %
48 g ----- x
x =48 % O
C)
Mm H2O
H: 2 x 1 = 2 g/mol
O: x 16 = 16 g/mol
````````````````````````````
Mm = 18 g /mol
HIDROGENO
18 g ----- 100 %
2 g ----- x
x = 11.11 % H
OXIGENO
18 g ---- 100 %
16 g ---- x
x = 88.88 % O
N: 2 x 14 = 28 g/mol
H: 4 x 1 = 4 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 80 g/mol
NITROGENO:
80 g ------ 100 %
28 g ------ x
x = 35 % N
HIDROGENO:
80 g ------ 100 %
4 g ------ x
x = 5 % H
OXIGENO:
80 g ------ 100 %
48 g ------ x
x = 60 % O
B) CaCO3
Mm CaCO3
Ca: 1 x 40 = 40 g/mol
C: 1 x 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````````
Mm = 100 g/mol
Calcio
100 g ----- 100 %
40 g ----- x
x = 40 % Ca
Carbono
100 g ----- 100 %
12 g ----- x
x = 12 % C
OXIGENO
100 g ----- 100 %
48 g ----- x
x =48 % O
C)
Mm H2O
H: 2 x 1 = 2 g/mol
O: x 16 = 16 g/mol
````````````````````````````
Mm = 18 g /mol
HIDROGENO
18 g ----- 100 %
2 g ----- x
x = 11.11 % H
OXIGENO
18 g ---- 100 %
16 g ---- x
x = 88.88 % O
Otras preguntas
Contabilidad,
hace 8 meses
Química,
hace 1 año
Física,
hace 1 año
Historia,
hace 1 año
Castellano,
hace 1 año