Question

calcular x= 7/2CC(q)
siendo:
SSSSSCCCSCCS(q)=3CCSCCS(2q)

S= Suplemento
C=Complemento
q= angulo

Answer 1

SSSSSCCCSCCS(q):
180 - (180 - (180 - (180 - (180 - (90 - (90 - (90 - (180 - (90 - (90 - (180 - q))))))
180 - (180 - (180 - (180 - (180 - (90 - (90 - (90 - (180 - (90 - (- 90 + q)))))))))
180 - (180 - (180 - (180 - (180 - (90 - (90 - (90 - (180 - (180 - q)))))))))
180 - (180 - (180 - (180 - (180 - (90 - (90 - (90 - (q))))))))
180 - (180 - (180 - (180 - (180 - (90 - (90 - (90 - q)))))))
180 - (180 - (180 - (180 - (180 - (90 - (q))))))
180 - (180 - (180 - (180 - (180 - (90 - q)))))
180 - (180 - (180 - (180 - (90 + q))))
180 - (180 - (180 - (90 - q)))
180 - (180 - (90 + q))
180 - (90 - q)
90 + q

3CCSCCS(2q):
3(90 - (90 - (180 - (90 - (90 - (180 - 2q))))))
3(90 - (90 - (180 - (90 - (- 90 + 2q)))))
3(90 - (90 - (180 - (180 - 2q))))
3(90 - (90 - (2q)))
3(90 - (90 - 2q))
3(2q)
6q

90 + q = 6q
90 = 5q
18 = q

Calcular:
 x = 7/2CC(q)
x = 7/2(90 - (90 - q))
x = 7/2(18)
x = 7(18)/2 = 63
          o
x = 7/36 = 0.194