Question

CALCULAR LA COMPOSICION PORCENTUAL DE C5H10O5

Answer 1

C₅H₁₀O₅

Mm
C = 5 x 12 = 60 g/mol
H = 10 x 1 = 10 g/mol
O = 5 x 16 = 80 g/mol
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         Mm = 150 g/mol

CARBONO

150 g ------ 100 %
  60 g ------  x

x = 40 % de C

HIDROGENO

150 g ----- 100 %
  10 g -----  x

x = 6.67 % de H

OXIGENO

150 g ----- 100 %
  80 g -----  x

x = 53.33 % O