Calcula "x" , de la siguiente figura
Respuestas a la pregunta
Respuesta:
⇒
3
x
−
7
=
8
+
6
x
+
12
Let's combine the terms on the right hand side:
⇒
3
x
−
7
=
6
x
+
20
Next, we can add 7 to both sides of the equation:
⇒
3
x
=
6
x
+
27
Subtract 6x from both sides:
⇒
−
3
x
=
27
Divide both sides of the equation by -3:
⇒
x
=
−
9
Answer link
Meave60
Jan 11, 2018
x
=
−
9
Explanation:
Solve:
3
x
−
7
=
8
+
6
(
x
+
2
)
Simplify
6
(
x
+
2
)
to
6
x
+
12
.
3
x
−
7
=
8
+
6
x
+
12
Subtract
3
x
from both sides.
−
7
=
8
+
6
x
+
12
−
3
x
Simplify.
−
7
=
8
+
3
x
+
12
Simplify
8
+
12
to
20
.
−
7
=
3
x
+
20
Subtract
20
from both sides.
−
20
−
7
=
3
x
Simplify.
−
27
=
3
x
Divide both sides by
3
.
−
27
3
=
x
Simplify.
−
9
=
x
Switch sides.
x
=
−
9
Answer link
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Impact of this question
468 views around the world
You can reuse this answer
Creative Commons License
iOS
Explicación paso a paso:⇒
3
x
−
7
=
8
+
6
x
+
12
Let's combine the terms on the right hand side:
⇒
3
x
−
7
=
6
x
+
20
Next, we can add 7 to both sides of the equation:
⇒
3
x
=
6
x
+
27
Subtract 6x from both sides:
⇒
−
3
x
=
27
Divide both sides of the equation by -3:
⇒
x
=
−
9
Answer link
Meave60
Jan 11, 2018
x
=
−
9
Explanation:
Solve:
3
x
−
7
=
8
+
6
(
x
+
2
)
Simplify
6
(
x
+
2
)
to
6
x
+
12
.
3
x
−
7
=
8
+
6
x
+
12
Subtract
3
x
from both sides.
−
7
=
8
+
6
x
+
12
−
3
x
Simplify.
−
7
=
8
+
3
x
+
12
Simplify
8
+
12
to
20
.
−
7
=
3
x
+
20
Subtract
20
from both sides.
−
20
−
7
=
3
x
Simplify.
−
27
=
3
x
Divide both sides by
3
.
−
27
3
=
x
Simplify.
−
9
=
x
Switch sides.
x
=
−
9
Answer link
Related questions
How do I determine the molecular shape of a molecule?
What is the lewis structure for co2?
What is the lewis structure for hcn?
How is vsepr used to classify molecules?
What are the units used for the ideal gas law?
How does Charle's law relate to breathing?
What is the ideal gas law constant?
How do you calculate the ideal gas law constant?
How do you find density in the ideal gas law?
Does ideal gas law apply to liquids?
Impact of this question
468 views around the world
You can reuse this answer
Creative Commons License
iOS