Calcula las siguientes potencias y ordenalas de mayor a menor
-(+5)³=
-(-6)(-6)=
(+2)8:(+2)5=
[(-8)¹]²=
(-9)5:(-9)5=
(-8)0=
-(-5)(-5)²=
(-14)7:(-14)5=
[(-4)²]²=
(+7)5:(+7)⁴=
2•(-4)²=
(-2)³(-2)=
(-6)7:(-6)5=
-(-3)⁴=
-[(-2)³]²=
(-2)5=
33⁴:33³=
2•(-2)³=
-6³=
(-1)(-1)²=
Ayuda por favor >n
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Explicación paso a paso:
Respuesta:
Explicación paso a paso:
-(+5)³= -(5x5x5)=-(125)
-(-6)(-6)=-(-6x-6)=-(36)=-36 menos por menos da +
(+2)8:(+2)5= (2x8) / (2x5) = 16/10 = 8/5
[(-8)¹]²= -(82x1)= -(82)=-64
(-9)5:(-9)5=(-9x5) / (-9x5) =-45 / -45 = 1
(-8)0= todo número elevado a la cero es uno así sea negativo
-(-5)(-5)²=-(-5)x(-5x-5)=5x25=+125
(-14)7:(-14)5=-2 / -(14/5)= (-10/5)/(-14/5)= -10/-14 = 5/7
[(-4)²]²=)(16)2=216
(+7)5:(+7)⁴=(7/5) / (7x7x7x7)= (7/5) / 2401 = (7/5)(1/2401) =7/(2401x5) = 7/12005 =1/1715
2•(-4)²=2x16=32 porque (-4x-4) = 16
(-2)³(-2)=-8x-2 = 16
(-6)7:(-6)5= 7/5
-(-3)⁴=-(81)
-[(-2)³]²=-(-26)= -64 resuelva (-2x-2x-2x-2x-2x-2)
(-2)5=-10
33⁴:33³= (33x33x33x33)/(33x33x33) = 33
2•(-2)³=2x-8= -16
-6³=-216
(-1)(-1)²=-1x(1)=-1
-6³=-216 20 (216,00)
-(+5)³= -(5x5x5)=-(125)
-(-3)⁴=-(81)
[(-8)¹]²= -(82x1)= -(82)=-64
-[(-2)³]²=-(-26)= -64 resuelva (-2x-2x-2x-2x-2x-2)
-(-6)(-6)=-(-6x-6)=-(36)=-36 menos por menos da +
2•(-2)³=2x-8= -16
(-2)5=-10
(-1)(-1)²=-1x(1)=-1
(+7)5:(+7)⁴=(7/5) / (7x7x7x7)= (7/5) / 2401 = (7/5)(1/2401) =7/(2401x5) = 7/12005 =1/1715
(-14)7:(-14)5=-2 / -(14/5)= (-10/5)/(-14/5)= -10/-14 = 5/7
(-9)5:(-9)5=(-9x5) / (-9x5) =-45 / -45 = 1
= 1 todo número elevado a la cero es uno así sea negativo
(-6)7:(-6)5= 7/5
(+2)8:(+2)5= (2x8) / (2x5) = 16/10 = 8/5
2•(-4)²=2x16=32 porque (-4x-4) = 16
(-2)³(-2)=-8x-2 = 16
33⁴:33³= (33x33x33x33)/(33x33x33) = 33
-(-5)(-5)²=-(-5)x(-5x-5)=5x25=+125
[(-4)²]²=)(16)2=216