Question

Calcula ayudarme, si me ayudas te doy coronita ​

Answer 1

a) - 101 / 45

$\frac{1}{5} - 2 + ( - \frac {4}{9} \: ) \\ \frac{9 - 90 - 20}{45} \\ - \frac{ 101}{45}$

b) 23 / 18

$\frac{5}{3} - ( - \frac{4}{9} \: ) + ( \frac{5}{ - 6} \: ) \\ \frac{5}{3} + \frac{4}{9} + \frac{5}{ - 6} = \frac{23}{18}$

c) 46 / 35

$1 - ( \frac{3}{ - 5} ) + ( - \frac{2}{7} ) \\ 1 - \frac{3}{ - 5} - \frac{2}{7} = 1 + \frac{3}{5} - \frac{2}{7} \\ \frac{35 + 21 - 10}{35} = \frac{46}{35}$

d) - 21 / 4

$- ( \frac{1}{ - 2} ) - 5 + ( \frac{ - 3}{4} ) \\ \frac{1}{ 2} - 5 + \frac{ - 3}{4} \\ \frac{1 \times 2}{2 \times 2} - 5 + \frac{ - 3}{4} \\ \frac{1 \times 2}{2 \times 2} - \frac{5}{1} + \frac{ - 3}{4} \\ \frac{2}{2 \times 2} - \frac{5}{1} + \frac{ - 3}{4} = \frac{2}{4} - \frac{5}{1} + \frac{ - 3}{4} \\ \frac{2}{4} - \frac{5 \times 4}{1 \times 4} + \frac{ - 3}{4} = \frac{2}{4} - \frac{20}{1 \times 4} + \frac{ - 3}{4} \\ \frac{2 - 20 - 3}{4} = \frac{21}{4}$