Question

ayúdenme xfas
K. (318-200)- 27.(-1) =
i. 10.(-2) -7.(-1)-5.2+7=
m. 3 - (5.2) + 12:(-7) - 4.(8-4) =​

Answer 1

K:

(318-200)- 27.(-1) =

=118−(27)(−1)

=118−(−27)

=145

I:

10.(-2) -7.(-1)-5.2+7=

=−20−(7)(−1)−5.2+7

=−20−(−7)−5.2+7

=−13−5.2+7

=−13−10+7

=−23+7

=−16

M:

3 - (5.2) + 12:(-7) - 4.(8-4) =

=3−10+12:−7−4(8−4)

=−7+12:−7−4(8−4)

=−7+−12:7−4(8−4)

=−61:7−4(8−4)

=−61:7−(4)(4)

=−61:7−16

=−173/7