Question

ayúdenme por favor ​

Answer 1

Respuesta:

$\frac{\sqrt{2x+5} -3 }{2}$

Explicación paso a paso:

*se sabe:

(a-b)(a+b)=a²-b²

*resolviendo:

$\frac{x-2}{3+\sqrt{2x+5} } \\\\(\frac{x-2}{3+\sqrt{2x+5} })(\frac{3-\sqrt{2x+5} }{3-\sqrt{2x+5} } )\\\frac{(x-2)(3-\sqrt{2x+5 )} }{3^{2}-(2x+5)} \\\frac{(x-2)(3-\sqrt{2x+5)} }{9-2x-5}\\\frac{(x-2)(3-\sqrt{2x+5)} }{4-2x}\\\frac{(x-2)(3-\sqrt{2x+5)} }{-2(x-2)}\\\frac{(3-\sqrt{2x+5)} }{-2}\\\frac{\sqrt{2x+5} -3 }{2}$