Question

Ayúdenme con estos problemas, xfavorr

Answer 1

Explicación paso a paso:

$a^{2} + 5a + 6 = (a + 2)(a + 3) \\ \frac{(a + 2)(a + 3)}{(a + 2)} \: eliminamos \: iguales \\ = (a + 3) \\ \\ caso2 \\ \\ 6 {x }^{2} - xy - 2 {y}^{2} = (3x - 2y)(2x + y) \\ \\ \frac{(3x - 2y)(y + 2x)}{(y + 2x)} \\ \\ = (3x - 2y)$

$caso \: 3$

$- 15 {x}^{2} - 8y^{2} + 22xy = (2y - 3x)(2y - 3x) \\ \\ = \frac{(2y - 3x)(2y - 3x)}{(2y - 3x)} \\ \\ = (2y - 3x)$

$caso \: 4 \\ \\ 5a^{2} + 8ab - 21b^{2} = (a + 3b)(5a - 7b) \\ \\ \frac{(a + 3b)(5a - 7b)}{(a + 3b)} \\ \\ = (5a - 7b)$

$caso \: 5 \\ \\ 14 {x}^{2} + 22x - 12 = (7x - 3)( 2x + 4) \\ \\ \frac{(7x - 3)( 2x + 4)}{(7x - 3)} \\ \\ = (2x + 4)$