Question

ayudeeeeeeeenme pls













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Answer 1

$( - {m}^{2} + 6 ) + ( - 4 {m}^{2} + 7m + 2 ) = \\ - {m}^{2} + 6 - 4 {m}^{2} + 7m + 2 = \\ ( - {m}^{2} - 4 {m}^{2} ) + 7m + (6 + 2) = \\ - 5 {m}^{2} + 7m + 8$

$( - 4 {x}^{4} + {x}^{2} - 4 ) + (5 {x}^{2} - 4) = \\ - 4 {x}^{4} + {x}^{2} - 4 + 5 {x}^{2} - 4 = \\ - 4 {x}^{4} + ( {x}^{2} + 5 {x}^{2} ) + ( - 4 - 4) = \\ - 4 {x}^{4} + 6 {x}^{2} + ( - 8) = \\ - 4 {x}^{4} + 6 {x}^{2} - 8$

$( - {t}^{3} + 5 {t}^{2} - 6t ) + (8 {t}^{2} - 8t) = \\ - {t}^{3} + 5 {t}^{2} - 6t + 8 {t}^{2} - 8t = \\ - {t}^{ 3} + (5 {t}^{2} + 8 {t}^{2} ) + ( - 6t - 8t) = \\ - {t}^{3} + 13 {t}^{2} + ( - 14t) = \\ - {t}^{3} + 13 {t}^{2} - 14t = \\ t( - {t}^{2} + 13t - 14 )$

$( - 3 {y}^{2} - 5y - 2 ) + ( - 7 {y}^{2} + 5y + 2) = \\ - 3 {y}^{2} - 5y - 2 - 7 {y}^{2} + 5y + 2 = \\ ( - 3 {y}^{2} - 7 {y}^{2} ) + ( - 5y + 5y) + ( - 2 + 2) = \\ - 10 {y}^{2}$

$(4 {v}^{3} - 3 {v}^{2} + 2v ) + (3 {v}^{3} + 6 {v}^{2} - 9v ) = \\ 4 {v}^{3} - 3 {v }^{2} + 2v + 3 {v}^{3} + 6 {v}^{2} - 9v = \\ (4 {v}^{3} + 3 {v}^{3} ) + ( - 3 {v}^{2} + 6 {v}^{2} ) + (2v - 9v) = \\ 7 {v}^{3} + 3 {v}^{2} + ( - 7v) = \\ 7 {v}^{3} + 3 {v}^{2} - 7v = \\ v(7 {v}^{2} + 3v - 7)$

$( - 4 {b}^{2} + 8b ) + ( - 4 {b}^{3} + 5 {b}^{2} - 8b ) = \\ - 4 {b}^{2} + 8b - 4 {b}^{3} + 5 {b}^{2} - 8b = \\ - 4 {b}^{3} + ( - 4 {b}^{2} + 5 {b}^{2} ) + (8b - 8b) = \\ - 4 {b}^{3} + {b}^{2} = \\ {b}^{2} ( - 4b + 1)$

$(3 {x}^{3} + 4 {x}^{2} ) + (3 {x}^{3} - 4{x}^{2} - 9x ) = \\ 3 {x}^{3} + 4 {x}^{2} + 3 {x}^{3} - 4 {x}^{2} - 9x = \\ (3 {x}^{3} + 3 {x}^{3} ) + (4 {x}^{2} - 4 {x}^{2} ) - 9x = \\ 6 {x}^{3} - 9x = \\ 3x(2 {x}^{2} - 3 )$

$( - 2 {k}^{3} - 7 {k}^{2} + 5k ) + (6 {k}^{2} + 3k) = \\ - 2 {k}^{3} - 7 {k}^{2} + 5k + 6 {k}^{2} + 3k = \\ - 2 {k}^{3} + ( - 7 {k}^{2} + 6 {k}^{2} ) + (5k + 3k) = \\ - 2 {k}^{3} + ( - {k}^{2} ) + 8k = \\ - 2 {k}^{3} - {k}^{2} + 8k = \\ k ( - 2 {k}^{2} - k + 8)$

$(7 {a}^{3} - 2a - 2) + ( - 5a + 3) = \\ 7 {a}^{3} - 2a - 2 - 5a + 3 = \\ 7 {a}^{3} + ( - 2a - 5a) + ( - 2 + 3) = \\ 7 {a}^{3} + ( - 7a) + 1 = \\ 7 {a}^{3} - 7a + 1$